6x^2=438

Solution for 6x^2=438 equation:

6x^2=438

We move all terms to the left:

6x^2-(438)=0

a = 6; b = 0; c = -438;
Δ = b2-4ac
Δ = 02-4·6·(-438)
Δ = 10512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10512}=\sqrt{144*73}=\sqrt{144}*\sqrt{73}=12\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{73}}{2*6}=\frac{0-12\sqrt{73}}{12}
=-\frac{12\sqrt{73}}{12}
=-\sqrt{73}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{73}}{2*6}=\frac{0+12\sqrt{73}}{12}
=\frac{12\sqrt{73}}{12}
=\sqrt{73}
$